12x^2+8x-340=0

Solution for 12x^2+8x-340=0 equation:

12x^2+8x-340=0

a = 12; b = 8; c = -340;
Δ = b2-4ac
Δ = 82-4·12·(-340)
Δ = 16384
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{16384}=128$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(8)-128}{2*12}=\frac{-136}{24}
=-5+2/3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(8)+128}{2*12}=\frac{120}{24}
=5
$